Electronics - Series Circuits - Discussion
Discussion Forum : Series Circuits - Filling the Blanks (Q.No. 2)
2.
If a 3.9 k
, a 7.5 k, and a 5.6 k resistor are connected in series with a 34 V source, the voltage dropped across the 7.5 k resistor equals _____.
, a 7.5 k, and a 5.6 k resistor are connected in series with a 34 V source, the voltage dropped across the 7.5 k resistor equals _____.Discussion:
2 comments Page 1 of 1.
KIRAN V said:
5 years ago
R(Total) = (3.9 k Ω + 7.5 k Ω + 5.6 k Ω) = 17 kΩ
V = 34 V.
Then, I = V/R = 34 / 17 k Ω = 2 m A.
Now, I = 2 m A & R = 7.5 kΩ
V = I*R = 2 m A * 7.5 kΩ = 15 V.
V = 34 V.
Then, I = V/R = 34 / 17 k Ω = 2 m A.
Now, I = 2 m A & R = 7.5 kΩ
V = I*R = 2 m A * 7.5 kΩ = 15 V.
(1)
RAHUL PRAJAPATI said:
1 decade ago
TOTAL R = 17 OHM
V = 34 V
THEN I = V/R = 34 / 17 = 2 AMP
NOW I = 2 AMP & R= 7.5 OHM
V = I*R = 2*7.5 = 15 v
V = 34 V
THEN I = V/R = 34 / 17 = 2 AMP
NOW I = 2 AMP & R= 7.5 OHM
V = I*R = 2*7.5 = 15 v
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