Electronics - Series Circuits - Discussion
Discussion Forum : Series Circuits - General Questions (Q.No. 41)
41.
How much current flows in the circuit in the given circuit?
20 
A
A60 A
A80 A
A140 A
ADiscussion:
3 comments Page 1 of 1.
Seenivasagan said:
1 decade ago
Using kirchaff's law,In the circuit the current remains same. So, take it as I,
9-(47k+27k+56k+20k)*I-12=0
9-12-(150k)*I=0;
150K*I=3;
I=3/150K;
I(current) = 20 micro amps.
9-(47k+27k+56k+20k)*I-12=0
9-12-(150k)*I=0;
150K*I=3;
I=3/150K;
I(current) = 20 micro amps.
Sreeyush Sudhakaran said:
1 decade ago
Veff = 12-9 = 3V
RT = 150 K
I=Veff/RT
I = (3/150)x10^-3
I =(1/5)x10^-4
I = 20x10^-6 = 20uA
RT = 150 K
I=Veff/RT
I = (3/150)x10^-3
I =(1/5)x10^-4
I = 20x10^-6 = 20uA
ABHISHEK said:
10 years ago
R = 47+27+56+2 = 150*10^3.
V = IR.
I = V/R = (12-9)/150*10^3 = 20*10^-6.
V = IR.
I = V/R = (12-9)/150*10^3 = 20*10^-6.
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