Electronics - Series Circuits - Discussion
Discussion Forum : Series Circuits - General Questions (Q.No. 8)
8.
In the given circuit, what type of failure will cause the voltage at point B to equal the voltage at point C?
Discussion:
8 comments Page 1 of 1.
Mahesh Babu said:
4 years ago
No Resistor never shorts.
Jamil hassan said:
8 years ago
If R2 is short. It is obvious no voltage drop and hence voltage are same at point B and C.
Nitin said:
1 decade ago
Vt = 28v.
Va = 28v.
Vb = Va-V1.
So Vc = Vb-V2.
Here,V2 = It*R2.
So if R2 goes short means R2=0 and also V2=0.
Then Vb = Vc.
Va = 28v.
Vb = Va-V1.
So Vc = Vb-V2.
Here,V2 = It*R2.
So if R2 goes short means R2=0 and also V2=0.
Then Vb = Vc.
Bilal khattak said:
1 decade ago
Vt=28v
Va=28v
Vb=Va-V1
Where V1=It*R1 and It=Vt/Rt
So Vc=Vb-V2
Where V2=It*R2
So if R2 goes short means R2=0 and also V2=0
Then Vb=Vc.
Va=28v
Vb=Va-V1
Where V1=It*R1 and It=Vt/Rt
So Vc=Vb-V2
Where V2=It*R2
So if R2 goes short means R2=0 and also V2=0
Then Vb=Vc.
Manoj mittal said:
1 decade ago
Here R2 will be short due to it voltage drop will be zero so voltage at point B equal to point C. If R2 will open then voltage between B and C is equal to between A and D.
Uday said:
1 decade ago
Resistance will not short at any time. Resistance failure means it will opens only.
(1)
Sunny said:
1 decade ago
The total current in circuit is i=28/10kohm=2.8ma.
From nodal analysis (Vb-Vc)/R2=2.8ma for Vb=Vc R2 must be zero.
Hence R2 is short circuited.
From nodal analysis (Vb-Vc)/R2=2.8ma for Vb=Vc R2 must be zero.
Hence R2 is short circuited.
(1)
Arun Jain said:
1 decade ago
The ans. should be right bcoz if we do R1 and R3 short than there must be some voltage drop across R2 and point B and C is not equal voltage and take option D(R2 is open)than CKT is not complite, so we can go with option B, In this B=C so that the voltage is equal at both the points.
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