Electronics - Semiconductor Principles - Discussion
Discussion Forum : Semiconductor Principles - General Questions (Q.No. 24)
24.
What is the voltage across R1 if the P-N junction is made of silicon?


Discussion:
23 comments Page 2 of 3.
Mohini sagariya said:
1 decade ago
0.7 is the Voltage across the pn diode so according to the kvl answer is 11.3
Sweta said:
1 decade ago
Sorry I can't understand please anyone can explain.
Aneesh cv dev said:
10 years ago
First active diode need for 0.7 voltage.
Since the voltage across R1 = 12-0.7 = 11.3.
Since the voltage across R1 = 12-0.7 = 11.3.
Chandradas s Mohan said:
9 years ago
0.7 v is the cutoff voltage of silicon.
Bushra said:
9 years ago
Sorry I can't understand this, Please help me.
Aravind said:
9 years ago
The silicon has 0.7 voltage barrier. So it blocks 0.7v from load source.
Therefore 12-0.7 = 11.3.
Likewise, germanium has 0.3 voltage barrier. therefore if PN junction is germanium then the answer will be 11.7.
Therefore 12-0.7 = 11.3.
Likewise, germanium has 0.3 voltage barrier. therefore if PN junction is germanium then the answer will be 11.7.
REYAZUDDIN ALAM said:
9 years ago
We know that break down voltage of si = 0.7v.
Silicon will consume 0.7v.
So, voltage across r1= 12.0.7 = 11.3v answer.
Silicon will consume 0.7v.
So, voltage across r1= 12.0.7 = 11.3v answer.
Srikanth said:
9 years ago
The silicon has 0.7 Cutoff voltage, So answer is11.3v/// Mostly used PN junction is Silicon.
RAPHAEL CHINEDU IKEM said:
9 years ago
0.7 is the voltage drop for silicon diode.
So when the 13V pass through the silicon diode, there will be a voltage drop of about 0.7V
i.e 13 - 0.7 = 12.3V.
So when the 13V pass through the silicon diode, there will be a voltage drop of about 0.7V
i.e 13 - 0.7 = 12.3V.
Kalyan polu said:
9 years ago
The diode cutoff voltage is 0.7 volts for silicon. So the remaining voltage of input will be obtained at the output i.e., 12-0.7 = 11.3v.
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