Electronics - Semiconductor Memory - Discussion
Discussion Forum : Semiconductor Memory - General Questions (Q.No. 2)
2.
How many storage locations are available when a memory device has twelve address lines?
Discussion:
7 comments Page 1 of 1.
Er. Lalbabu Sahani said:
9 years ago
I agree with you @Vijay.
12 address lines can have 2^12 memory locations.
12 address lines can have 2^12 memory locations.
(1)
Brijesh said:
1 decade ago
Each line can be addressed either 0 or 1 so each address line can be addressed in two ways. There are total 12 address line
(2*2*2.......2) (12 times therefore 2^12 address line are required).
(2*2*2.......2) (12 times therefore 2^12 address line are required).
Vijay said:
1 decade ago
The electronic devises deals with binary number(2).
So 12 address lines can have 2^12 memory locations.
So 12 address lines can have 2^12 memory locations.
Dhiaj said:
1 decade ago
Answer by sainchaitanya is correct.
HARPREET said:
1 decade ago
(2)of power P= M
M= MO. OF MEMORIES LOCATIONS
P= NO . OF ADDRESS LINES
SO GIVEN DATA WAS " P "
GET "M"
M= MO. OF MEMORIES LOCATIONS
P= NO . OF ADDRESS LINES
SO GIVEN DATA WAS " P "
GET "M"
Saichaitanya said:
1 decade ago
The storage locations can be decide by using the following formula:
(2 power n) this gives the storage locations, where n is the number of address lines.
Here the no. of address lines are 12 i.e. n=12
Therefore (2^12) gives 4096.
(2 power n) this gives the storage locations, where n is the number of address lines.
Here the no. of address lines are 12 i.e. n=12
Therefore (2^12) gives 4096.
GLADWIN said:
1 decade ago
2power 12 storage locations
fof n lines 2^n locations are available
fof n lines 2^n locations are available
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers