### Discussion :: Semiconductor Memory - General Questions (Q.No.2)

Gladwin said: (Jan 3, 2011) | |

2power 12 storage locations fof n lines 2^n locations are available |

Saichaitanya said: (Mar 29, 2011) | |

The storage locations can be decide by using the following formula: (2 power n) this gives the storage locations, where n is the number of address lines. Here the no. of address lines are 12 i.e. n=12 Therefore (2^12) gives 4096. |

Harpreet said: (May 13, 2011) | |

(2)of power P= M M= MO. OF MEMORIES LOCATIONS P= NO . OF ADDRESS LINES SO GIVEN DATA WAS " P " GET "M" |

Dhiaj said: (Aug 29, 2011) | |

Answer by sainchaitanya is correct. |

Vijay said: (Mar 16, 2013) | |

The electronic devises deals with binary number(2). So 12 address lines can have 2^12 memory locations. |

Brijesh said: (Nov 14, 2013) | |

Each line can be addressed either 0 or 1 so each address line can be addressed in two ways. There are total 12 address line (2*2*2.......2) (12 times therefore 2^12 address line are required). |

Er. Lalbabu Sahani said: (May 10, 2016) | |

I agree with you @Vijay. 12 address lines can have 2^12 memory locations. |

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