Electronics - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 45)
45.
What is the bandwidth of the circuit in the given circuit?
Discussion:
4 comments Page 1 of 1.
Vandana said:
1 decade ago
Please give me the explanation.
Maahi said:
1 decade ago
We Know B.W.=f/Q.
so f=1/(2*3.141*(L*C)^0.5)
Q=1/R*(L/C)^0.5
B.W.=275.879909 Hz.
so f=1/(2*3.141*(L*C)^0.5)
Q=1/R*(L/C)^0.5
B.W.=275.879909 Hz.
Raj said:
1 decade ago
Bw = f/q,
So Bw = 1/R,
bw = 275.87.
So Bw = 1/R,
bw = 275.87.
EliDawn said:
9 years ago
XL = 130.
XL = 2 (pi) (f) (L).
F = 130 / (2 * pi * 75 * 10^-3).
F = 275.9 Hz.
XL = 2 (pi) (f) (L).
F = 130 / (2 * pi * 75 * 10^-3).
F = 275.9 Hz.
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