Electronics - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 11)
11.
What is the resonant frequency in the given circuit?
Discussion:
21 comments Page 2 of 3.
Lakshmi said:
10 years ago
Fo = 1/2*LC"R^2/L^2.
In this circuit we must use this formula right?
In this circuit we must use this formula right?
Jeewan said:
1 decade ago
What is the significance of Rw?
Hussain said:
1 decade ago
Please provide the explanation
Fr = 1/(2*pi*sqrt(L*C));
L = 75mH C = 0.033 UF on substituting these values in above formula Fr = 0.101 KHz.
where i went wrong?
Fr = 1/(2*pi*sqrt(L*C));
L = 75mH C = 0.033 UF on substituting these values in above formula Fr = 0.101 KHz.
where i went wrong?
Nilesh said:
1 decade ago
@Hussain said is right because after calculation it comes 0.101khz not 3.2khz
Check out calculation correctly
Fr = 1/(2*pi*sqrt(L*C));
L = 75mH C = 0.033 UF on substituting these values in above formula Fr = 0.101 KHz.
Check out calculation correctly
Fr = 1/(2*pi*sqrt(L*C));
L = 75mH C = 0.033 UF on substituting these values in above formula Fr = 0.101 KHz.
Weldeabreha beyene said:
1 decade ago
@Guru.
Let me explain, it is because resonance does not bother whether, series or parallel, simply (C&L).
Let me explain, it is because resonance does not bother whether, series or parallel, simply (C&L).
Guru said:
1 decade ago
It is parallel resonance circuit then why you are applying series resonance formula please. Explain me.
Monica said:
1 decade ago
@Manikanta
Here Rw is nothing resistance but it is simply given its not of use
Resonant Frequency=1/(2*pi*sqrt(L*C))
=1/(2*pi*qrt(75*10^-3*0.033*10^-6))
= 31.99
=3.2khz
Here Rw is nothing resistance but it is simply given its not of use
Resonant Frequency=1/(2*pi*sqrt(L*C))
=1/(2*pi*qrt(75*10^-3*0.033*10^-6))
= 31.99
=3.2khz
Manikanta said:
1 decade ago
Here what is Rw?
Yogesh said:
1 decade ago
@Hussain
you insert 1000 for inducter and (e-6) for capacitor Milli and you value.
you insert 1000 for inducter and (e-6) for capacitor Milli and you value.
Razif said:
1 decade ago
F = 1/(2*pi*sqrt(L*C)) = 1/(2*pi*4.98*10^-5) = 3.2 kHz
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