Electronics - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 11)
11.
What is the resonant frequency in the given circuit?
Discussion:
21 comments Page 1 of 3.
Monica said:
1 decade ago
@Manikanta
Here Rw is nothing resistance but it is simply given its not of use
Resonant Frequency=1/(2*pi*sqrt(L*C))
=1/(2*pi*qrt(75*10^-3*0.033*10^-6))
= 31.99
=3.2khz
Here Rw is nothing resistance but it is simply given its not of use
Resonant Frequency=1/(2*pi*sqrt(L*C))
=1/(2*pi*qrt(75*10^-3*0.033*10^-6))
= 31.99
=3.2khz
Nilesh said:
1 decade ago
@Hussain said is right because after calculation it comes 0.101khz not 3.2khz
Check out calculation correctly
Fr = 1/(2*pi*sqrt(L*C));
L = 75mH C = 0.033 UF on substituting these values in above formula Fr = 0.101 KHz.
Check out calculation correctly
Fr = 1/(2*pi*sqrt(L*C));
L = 75mH C = 0.033 UF on substituting these values in above formula Fr = 0.101 KHz.
Pushpendra chaurasiya said:
1 decade ago
When i calculated first my ans was 0.101
n now my ans is 3.2KHz
Let me expalin,
Fr = 1/[2*3.14*sqrt{(75*10^-3)(0.033*10^-6)}]
= 1/[2*3.14*sqrt{2.475*10^-9}]
=1/[2*3.14*4.975*10^-5]
=1/[3.124*10^-4]
n now my ans is 3.2KHz
Let me expalin,
Fr = 1/[2*3.14*sqrt{(75*10^-3)(0.033*10^-6)}]
= 1/[2*3.14*sqrt{2.475*10^-9}]
=1/[2*3.14*4.975*10^-5]
=1/[3.124*10^-4]
(1)
Virendra said:
9 years ago
Given 3.2 kHz is the right answer.
As we know that sqrt of 100 is 10 but sqrt of 10 will be 3.1.
So by changing the sqrt of given value 2.475 as 24.75 will different.
As we know that sqrt of 100 is 10 but sqrt of 10 will be 3.1.
So by changing the sqrt of given value 2.475 as 24.75 will different.
Hussain said:
1 decade ago
Please provide the explanation
Fr = 1/(2*pi*sqrt(L*C));
L = 75mH C = 0.033 UF on substituting these values in above formula Fr = 0.101 KHz.
where i went wrong?
Fr = 1/(2*pi*sqrt(L*C));
L = 75mH C = 0.033 UF on substituting these values in above formula Fr = 0.101 KHz.
where i went wrong?
Afash said:
1 decade ago
First divide 75 on 1000 and .033 on 1000000, multiply both and simply take sqrt. Your answer will come correct. Don't you worry. @Mr.Hussain.
(1)
Weldeabreha beyene said:
1 decade ago
@Guru.
Let me explain, it is because resonance does not bother whether, series or parallel, simply (C&L).
Let me explain, it is because resonance does not bother whether, series or parallel, simply (C&L).
Guru said:
1 decade ago
It is parallel resonance circuit then why you are applying series resonance formula please. Explain me.
Akki said:
1 decade ago
Dude you are applying correct formula you once again check your calculation m getting correct ans.
ANAND said:
9 years ago
It's a parallel resonance circuit so, why you apply the formula of series resonance circuit?
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