Electronics - RLC Circuits and Resonance - Discussion

30. 

What is the current through the capacitor in the given circuit?

[A]. 3.5 mA
[B]. 5.5 mA
[C]. 9 mA
[D]. 11.4 mA

Answer: Option A

Explanation:

No answer description available for this question.

Gaurav said: (Aug 6, 2011)  
Vc=I*Xc
In parallel circuit Voltage is same at all the points.
V=12V, Xc=3386.27. I=12/3386.27
I=3.53mA

Tommy said: (Oct 18, 2013)  
How do you get Xc = 3386.27. Thanks.

Om Prakash Bharti said: (Jan 15, 2014)  
Xc = 1/wc = 1/2*pi*f*C.

= 1/2*3.14*47000*0.001*10^-6.

= 3386.27.

Afash said: (Jan 16, 2014)  
Very simple:

Xc = 1/2*pi*f*C.

So,
Xc = 1000000/2*Pi*47*1000*0.001.

So you will get 3386.275.
Then I = 12/3386.275.

I=3.543mA.

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