Discussion :: RLC Circuits and Resonance - General Questions (Q.No.26)
What is the bandwidth in the given circuit. If the winding resistance of the coil is 12 ?
Answer: Option A
No answer description available for this question.
|Deepti said: (May 18, 2011)|
|Kiran said: (Nov 2, 2011)|
|Monalisha said: (Dec 21, 2013)|
|We know, q=wL/R OR 2*pi*f*L/R = f/B.W.
f = 1/2*pi*sqrt(L*C) = 53650HZ = 53.65KHZ.
q = 2*Pi*f*L/R = 8.32.
B.W = f/q = 6.4KHZ.
|Emil Lagman said: (Mar 5, 2015)|
|R = 150+12 = 162 ohms.
BW = R/2*pi*L.
BW = 162/2*3.1416*4 mH = 6.44 kHz.
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