Electronics - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - True or False (Q.No. 2)
2.
The current through the inductor is 5 amps.
Discussion:
1 comments Page 1 of 1.
Subanu said:
2 months ago
Xl = 2 * π * f * L
= 2 * 3.14 * 1 * 10^3 * 1 * 10^-3.
XL = 6.28.
Generally, in parallel circuit the voltage across each element is the same when there are no intermediate elements present in that wire.
So the V across the Inductor is 300V.
I = V/XL .
= 300/6.28,
= 47.7A.
= 2 * 3.14 * 1 * 10^3 * 1 * 10^-3.
XL = 6.28.
Generally, in parallel circuit the voltage across each element is the same when there are no intermediate elements present in that wire.
So the V across the Inductor is 300V.
I = V/XL .
= 300/6.28,
= 47.7A.
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