Electronics - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 22)
22.
What is the current phase angle for a parallel RLC circuit when IL = 15.3 A, IC = 0.43 A, and IR = 3.5 A?
Discussion:
7 comments Page 1 of 1.
Sadaf said:
1 decade ago
In RLC circut phase angle depends upon values of Xc,XL.
When XL>Xc(which occurs at high frequencies), the phase angle is positive, signifying that the current lags behind the applied voltage. And if Xc>XL then circuit is capacitive so current leads voltage and angle will be negative.
In given question Ic<IL.
Ic=Vs/Xc,IL=Vs/XL so,
(Vs/Xc)<(Vs/XL).
or XL<Xc that's why ans is -76.
When XL>Xc(which occurs at high frequencies), the phase angle is positive, signifying that the current lags behind the applied voltage. And if Xc>XL then circuit is capacitive so current leads voltage and angle will be negative.
In given question Ic<IL.
Ic=Vs/Xc,IL=Vs/XL so,
(Vs/Xc)<(Vs/XL).
or XL<Xc that's why ans is -76.
Vid said:
1 decade ago
tan-1(reactance current/ir)=tan-1((15.3-0.43)/3.5)=76.755
Inductance current is more.
In inductor current lags voltage
Inductance current is more.
In inductor current lags voltage
Navu said:
1 decade ago
Can anyone tell me please Why the phase angle come negative ?
Sree said:
1 decade ago
Ys vid is right but formula must b as -tan inv (xl/r).
Chayan said:
1 decade ago
For parallel RLC circuit.
Formula is tan-1(Ic-Il/Ir).
Formula is tan-1(Ic-Il/Ir).
Mukund said:
1 decade ago
Does anyone know the solution of this problem?
Rakesh said:
1 decade ago
Please give solution for this problem.
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