Electronics - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 21)
21.
What is the true power consumed in a 30 V series RLC circuit if Z = 20 ohms and R = 10 ohms?
Discussion:
14 comments Page 2 of 2.
Simi said:
9 years ago
True power= I^2 * R.
Reactive Power = I^2 * X.
Apparent Power = I^2 * Z.
Here, I = V/Z = 30 / 20 = 3/2.
True power =(3/2)^2 * 10 = 22.5W.
Reactive Power = I^2 * X.
Apparent Power = I^2 * Z.
Here, I = V/Z = 30 / 20 = 3/2.
True power =(3/2)^2 * 10 = 22.5W.
(1)
Dhaval pujara said:
8 years ago
Here given,
V = 30v
Z = 20ohms
I = v/z
I=??
Then,
True power(p) = i^2*r.
V = 30v
Z = 20ohms
I = v/z
I=??
Then,
True power(p) = i^2*r.
Satish said:
7 years ago
Thanks @Vishal.
Marvin said:
4 years ago
G = Re(Z) = R/Z^2 = 0.025 Ohm;
Active power dissipates only on active resistance (conductivity)
P = U^2G = 30^2 * 0.025 = 22.5 W.
Active power dissipates only on active resistance (conductivity)
P = U^2G = 30^2 * 0.025 = 22.5 W.
(1)
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