Electronics - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 4)
4.
How much current will flow in a 100 Hz series RLC circuit if VS = 20 V, RT = 66 ohms, and XT = 47 ohms?
Discussion:
17 comments Page 1 of 2.
ANAMIKA said:
1 decade ago
I = V/Z.
I = 20/sqrt(66^2+47^2).
I = 0.24684 apro.
I = ~247mA.
I = 20/sqrt(66^2+47^2).
I = 0.24684 apro.
I = ~247mA.
(3)
Krupa said:
1 decade ago
Z = sqrt((66^2)+(47^2)).
Z = 81.024 ohms.
V = IZ.
I = V/Z = 20/81.024 = 0.24684 = 246.84mA = 247mA.
Z = 81.024 ohms.
V = IZ.
I = V/Z = 20/81.024 = 0.24684 = 246.84mA = 247mA.
(2)
Science mani said:
1 decade ago
I=Vs/Z;
Z=sqrt(R^2+X^2);
Z=sqrt(R^2+X^2);
(1)
Satish said:
3 years ago
I think I = v/r.
Saranya p.m said:
1 decade ago
Please give me the solutions of these kinds of problems.
Syed Shakeeb said:
4 years ago
I = V ÷ √(R^2+xt^2).
Mukesh soni said:
6 years ago
Rt= 66 * 66= 4356
Xt= 47 * 47= 2209
Z= √1/2 (4356+2209)
√1/2 ( 6565).
Near about = 82,
I = v/ z,
I =20/82 =247map.
Xt= 47 * 47= 2209
Z= √1/2 (4356+2209)
√1/2 ( 6565).
Near about = 82,
I = v/ z,
I =20/82 =247map.
Kamini said:
7 years ago
Your solution is very easy, thanks @Anamika.
Naveen said:
8 years ago
You are correct @Anila.
Vikash baghel said:
8 years ago
Very nice, Thanks.
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