Electronics - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 41)
41.
What is the power factor?
Discussion:
14 comments Page 2 of 2.
Murugan said:
7 years ago
In parallel rlc circuit.
Z=1/√((1÷r)^2+(1÷xl-1÷xc)^2).
i=v/z.
Power factor=true power/apparent power.
True power=i^2*r.
Apparent power=Vs * i.
Therefore power factor=i^2*r/Vs*i.
@Gasim your formula is a series circuit.
Z=1/√((1÷r)^2+(1÷xl-1÷xc)^2).
i=v/z.
Power factor=true power/apparent power.
True power=i^2*r.
Apparent power=Vs * i.
Therefore power factor=i^2*r/Vs*i.
@Gasim your formula is a series circuit.
Alvin said:
7 years ago
I Can't get this. Please, someone, explain in clear.
Pritam said:
5 years ago
Agree @Arun Sundar.
PF=z/R is working.
PF=z/R is working.
Pritam said:
5 years ago
PF= R/Z (for series).
pF= Z/R (for Parallel).
pF= Z/R (for Parallel).
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