Electronics - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 9)
9.
What is the total current?
Discussion:
19 comments Page 2 of 2.
Elkaa said:
1 decade ago
When I calculate xl=18840 ohm, xc= 5308 xl-xc=13532 ohm
z =3836 and 497/3836 =129 ma.
please confirm where this would be wrong
best regards
thanks in advance
z =3836 and 497/3836 =129 ma.
please confirm where this would be wrong
best regards
thanks in advance
Sri said:
1 decade ago
I appreciate @Ali's answer but small correction in formula the Ix and Ic should not be individually squared and their difference should be squared inside the formula.
Vijay Bhovani said:
1 decade ago
You can't add directly the current because there is a phase differences.
We can considered the admittance.
Y= 1/R+j(WC-1/WL).
WC=1/Xc=188.4*10^-6 ohm.
1/WL=1/Xl=53.07*10^-6.
1/R=250*10^-6.
WC-1/WL=135.33*10^-6.
So total admittance,
Y=284.278*10^-6.
So,
I = V*Y = 497*284.278*10^-6 = 141.286 mA.
We can considered the admittance.
Y= 1/R+j(WC-1/WL).
WC=1/Xc=188.4*10^-6 ohm.
1/WL=1/Xl=53.07*10^-6.
1/R=250*10^-6.
WC-1/WL=135.33*10^-6.
So total admittance,
Y=284.278*10^-6.
So,
I = V*Y = 497*284.278*10^-6 = 141.286 mA.
Amit singh said:
1 decade ago
Ali is correct because we can't forget vector quantities. So answer is 141ma.
Chandrani said:
1 decade ago
Thanks all. Specially Vasu n Ali.
Ali said:
1 decade ago
Vasu is correct till caculating Ir,Ic,Il
how we forget vector quantities
I=(Ir^2+(Il^2-Ic^2))^1/2
I=141mA
how we forget vector quantities
I=(Ir^2+(Il^2-Ic^2))^1/2
I=141mA
Vasu said:
1 decade ago
What lakshmi said is correct absolutely. The formula is I=Ir+Ic+Il
where in Ir=v/r
Ic=V/Xc and Il=V/Xl;
wherein Xc=1/(wc) and Xl=wl.
so we get Ir=0.12425,Ic=0.0936,Il=0.0263
So by totalling we get Itotal= 244 mA
where in Ir=v/r
Ic=V/Xc and Il=V/Xl;
wherein Xc=1/(wc) and Xl=wl.
so we get Ir=0.12425,Ic=0.0936,Il=0.0263
So by totalling we get Itotal= 244 mA
Lakshmi said:
1 decade ago
The answer in 244m. Because we need to add currents in each branch since its a parallel circuit! hope its noted:).
Fatjona said:
1 decade ago
Is wrong because the RLC circuits is a parallel circuits and the total impendance is not in this form.
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