Electronics - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 9)
9.
What is the total current?
Discussion:
19 comments Page 1 of 2.
Syed Shakeeb said:
3 years ago
Thanks @Vikash.
Nesma said:
4 years ago
How we determine Xc and XL? Please explain me.
Vikash kushwaha said:
5 years ago
Let I = I1 + I2 + I3.
NOW Xl=2πfL = 2 x 3.14 x 750x4 ~ 18850ohm.
also Xc=1÷{2πfC}= 2 x 3.14 x 0.04 x 10^-6~ 5305ohm.
I= √{(497/4000)^2 + ((497/18850)-(497/5305)^2.
I= ~0.141A = 141mA.
NOW Xl=2πfL = 2 x 3.14 x 750x4 ~ 18850ohm.
also Xc=1÷{2πfC}= 2 x 3.14 x 0.04 x 10^-6~ 5305ohm.
I= √{(497/4000)^2 + ((497/18850)-(497/5305)^2.
I= ~0.141A = 141mA.
MarkT said:
5 years ago
The answer to the choices is correct!
Xl=2piFL= 6000pi.
Xc=1/2piFC=5305.16477.
Then solve for the total impedance of RLC circuit using.
Z=1/square root (1/R^2+1/Xc^2+1/Xl^2).
Z= 3517.007 ohms.
Therefore using Ohms law,
I=V/Z= 497V/3517.007= 141.31mA.
I hope it helps!
Xl=2piFL= 6000pi.
Xc=1/2piFC=5305.16477.
Then solve for the total impedance of RLC circuit using.
Z=1/square root (1/R^2+1/Xc^2+1/Xl^2).
Z= 3517.007 ohms.
Therefore using Ohms law,
I=V/Z= 497V/3517.007= 141.31mA.
I hope it helps!
Ram said:
6 years ago
V=ir.
I=v/r.
I=497/4.
124. 25.
I=v/r.
I=497/4.
124. 25.
Deepu said:
8 years ago
You are correct @Vijay.
But Can anyone explain why can't we use formula?
Is= √((V/R)^2+((V/XL)-(V/XC))^2).
But Can anyone explain why can't we use formula?
Is= √((V/R)^2+((V/XL)-(V/XC))^2).
KIRAN V said:
9 years ago
You are correct @Vijay Bhovani.
Heshan Shalanka said:
10 years ago
Guys this is how calculated this in J operation theories.
XC = 5305 and XL+18840.
(4000<0 degree)(-5305i)/((-5305i+4000<0)) = 3193.848<-37.016 degrees.
And then,
(3193.848<-37.016 degrees)(18840i)/((3193.848<-37.016 degree)+(18840i)).
This equal to 3517.1255 ohm.
And i.e. the total impedance.
So that formula of V = IR.
I = 497/3517.1255 = 0.141308 Amp = 141.308 mA.
XC = 5305 and XL+18840.
(4000<0 degree)(-5305i)/((-5305i+4000<0)) = 3193.848<-37.016 degrees.
And then,
(3193.848<-37.016 degrees)(18840i)/((3193.848<-37.016 degree)+(18840i)).
This equal to 3517.1255 ohm.
And i.e. the total impedance.
So that formula of V = IR.
I = 497/3517.1255 = 0.141308 Amp = 141.308 mA.
Chardice said:
10 years ago
As we analyze the circuit it is a parallel RLC so we need to get the reciprocal of R, XL, XC that is conductance, susceptance in order to get the admittance.
Rajendra said:
1 decade ago
141mA is correct answer.
Use formula total current = 1/2(Ir2+square root(Il-Ic)2).
Use formula total current = 1/2(Ir2+square root(Il-Ic)2).
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