Electronics - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 35)
35.
What is the impedance of the circuit?


Discussion:
4 comments Page 1 of 1.
Vasu said:
1 decade ago
The impedance Z=sq.root( R^2 +(Xc-Xl)^2).
Ben said:
7 years ago
Please explain the answer.
Jimuel E. said:
6 years ago
First look for Xc and Xl.
Xl=2*Pi*f*C
Xc=1/2*Pi*f*L
Then, Z=sqrt(R^2+(Xl-Xc)^2)
Xl=2*Pi*f*C
Xc=1/2*Pi*f*L
Then, Z=sqrt(R^2+(Xl-Xc)^2)
Preci said:
4 years ago
The impedance z=""R^2+(Xl-Xc)^2.
R=10000ohms,
Xl=2πfl=2*3.142*1500*3=28278ohms.
Xc=1/2πfc = 1/2*3.142*1500*0.01*10^-6 = 21217.9ohms.
Z = 1000^2+(28278-21217.9)^2.
Z = 100000000+49845012.01.
Z = 149845012.
12241.12ohms or 12.2kohms i.e option A.
R=10000ohms,
Xl=2πfl=2*3.142*1500*3=28278ohms.
Xc=1/2πfc = 1/2*3.142*1500*0.01*10^-6 = 21217.9ohms.
Z = 1000^2+(28278-21217.9)^2.
Z = 100000000+49845012.01.
Z = 149845012.
12241.12ohms or 12.2kohms i.e option A.
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