Electronics - RL Circuits - Discussion
Discussion Forum : RL Circuits - Filling the Blanks (Q.No. 9)
9.
The cutoff frequency of the circuit in the given circuit is approximately equal to _____.
Discussion:
1 comments Page 1 of 1.
Dinesh said:
1 decade ago
At cutoff frequency XL= R.
2*pi*f*L = R.
f = R/(2*pi*L).
f = 220/(2*3.1415*96*10^-3).
f = 364.73.
f = 365Hz.
2*pi*f*L = R.
f = R/(2*pi*L).
f = 220/(2*3.1415*96*10^-3).
f = 364.73.
f = 365Hz.
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