Electronics - RL Circuits - Discussion
Discussion Forum : RL Circuits - True or False (Q.No. 2)
2.
The impedance of the circuit in the given circuit is 110 
.
Discussion:
4 comments Page 1 of 1.
Vipul said:
1 decade ago
z = sqrt[(xl1+xl2)^2+r^2].
= sqrt[(50+20)^2 + 40^2.
= sqrt[4900+1600].
= 80.62 ohm.
= sqrt[(50+20)^2 + 40^2.
= sqrt[4900+1600].
= 80.62 ohm.
Simran said:
1 decade ago
Why there is a square of resistance?
Asma Asghar janjua said:
9 years ago
I think so, in this case, the answer is false.
The one end of the resistor becomes is floating so it is not included in finding impedance r = 0.
Z = sqrt[(50+20) ^2].
Z = 70 ohm.
The one end of the resistor becomes is floating so it is not included in finding impedance r = 0.
Z = sqrt[(50+20) ^2].
Z = 70 ohm.
Rao said:
5 years ago
It should be Z= √[R^2 + (Xl-XC) ^2].
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