Electronics - RL Circuits - Discussion
Discussion Forum : RL Circuits - General Questions (Q.No. 1)
1.
As frequency increases
Discussion:
9 comments Page 1 of 1.
SAMurtza said:
6 years ago
Can be seen via MATLAB (Option C is correct)
w=0:1/10:2*π;
% RL Impedance Increases.
R=1; L=1;
Zs=R+j*w*L;
Zp=1./(1./R+1./j*w*L);
% normalized plots.
plot(w,abs(Zs)/max(abs(Zs)),w,abs(Zp)/max(abs(Zp))).
w=0:1/10:2*π;
% RL Impedance Increases.
R=1; L=1;
Zs=R+j*w*L;
Zp=1./(1./R+1./j*w*L);
% normalized plots.
plot(w,abs(Zs)/max(abs(Zs)),w,abs(Zp)/max(abs(Zp))).
SAMurtza said:
6 years ago
Z(w)_Series=R+jwL.
Z(0)_Series= R & |Z(infinite)_Series|= infinite (w increases , |Z| increases in SERIES) [Open at High frequency].
Z(w)_Parallel=1/(1/R-j/wL) .
|Z(0)_Parallel |=infinite & Z(infinite )_Parallel = R ( w increases , |Z| decreases in PARALLEL) [Short at DC].
Z(0)_Series= R & |Z(infinite)_Series|= infinite (w increases , |Z| increases in SERIES) [Open at High frequency].
Z(w)_Parallel=1/(1/R-j/wL) .
|Z(0)_Parallel |=infinite & Z(infinite )_Parallel = R ( w increases , |Z| decreases in PARALLEL) [Short at DC].
Jyothis said:
8 years ago
Find effective impedance of both series and parallel circuits. Analyse what happens when omega increases.
Raheel ahmed said:
1 decade ago
When the frequency of Parallel RL Circuit Increases, XL increases which causes IL (current through inductor) decreases. Decrease in IL causes It (It=Il+Ir) to decrease, which means by relation IT=Vs/Zt, the Zt (Total Impedance) Increases.
JAydeep Gidhvani said:
1 decade ago
Z=impedance
Z=R+XL
XL=2*Pi*F*L.
F Increase
XL Increase
SO Impedance increase.
Z=R+XL
XL=2*Pi*F*L.
F Increase
XL Increase
SO Impedance increase.
Bhanu said:
1 decade ago
In parallel the real impedence is in dinominator so optiion c is coorrect.
Sri Harshith Rajam said:
1 decade ago
Inductive Impedance (X)= Omega*Inductance
As omega is directly proportional to the frequency (2*pi*f) , the impedance increases and the inductor circuit tends to enter into the open circuit state !
As omega is directly proportional to the frequency (2*pi*f) , the impedance increases and the inductor circuit tends to enter into the open circuit state !
Situ dash said:
1 decade ago
In both series & parallel
Xl=2*pi*f*L
So as freq increases Xl value increases & hence impedance increases.
Xl=2*pi*f*L
So as freq increases Xl value increases & hence impedance increases.
Dinesh said:
1 decade ago
Xl=2pifl. In both the cases inductive reactance will increase with respect to frequency.
Hence increase in impedence.
Hence increase in impedence.
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