Electronics - RL Circuits - Discussion
Discussion Forum : RL Circuits - General Questions (Q.No. 9)
9.
What is the magnitude of the phase angle between the source voltage and current when a 100 mH inductor with an inductive reactance of 6 k
and a 1 k resistor are in series with a source?
and a 1 k resistor are in series with a source?Discussion:
5 comments Page 1 of 1.
Vasu said:
1 decade ago
The formula is theta (phase angle) = Tan ^-1 (WL/R)
Hanish said:
1 decade ago
Whether it is XL/r or wL/r....if it is w(omega) we need frequency to calculate.
Satish said:
1 decade ago
If frequency is not given just take it as 50 Hz.
And for that value only the answer is 80.5895 which approximately equal to 81.
XL= 6 Kohm + inductive reactance of 100mh (2*3. 14*50*100*10^-3).
And for that value only the answer is 80.5895 which approximately equal to 81.
XL= 6 Kohm + inductive reactance of 100mh (2*3. 14*50*100*10^-3).
Alan H said:
1 decade ago
Phase angle = tan^-1(XL/R).
XL is already given (6). R = (1) (both are in K ohms).
tan^-1(6/1) = 80.537.
tan^-1 = Inverse of tan.
XL = Inductive reactance.
6 K ohm is the inductive reactance of the 100 mH inductor - as stated in the question.
XL is already given (6). R = (1) (both are in K ohms).
tan^-1(6/1) = 80.537.
tan^-1 = Inverse of tan.
XL = Inductive reactance.
6 K ohm is the inductive reactance of the 100 mH inductor - as stated in the question.
(1)
Rajan said:
9 years ago
Yes, agree with you @Alan H.
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