Electronics - RL Circuits - Discussion

Here, Ir= 24/45= .533
Il= 24/1100= .02181

phase angle for parallel RL ckt= atan (Il/Ir)

So, ans= atan (.02181/.533) (in degrees)

Phase angle = -tan-1(IL/ IR).

Phase angle = -tan(.02181/.533) (in degrees).

= 2.3°

No need to convert it into current.

Phase angle = (inv)tan(R/XL) (in degrees).

Phase angle = (inv)tan(45/1100) (in degrees).

= 2.3°

@Ritu, Titos: conversion to current will lead to same answer. The current will again be divided, result=1. The only thing remaining will be resistance and impedance.

Search google for phase angle explanation and formula.

Phase angle = image part/real part.
=XL/R.

Phase angle:

Tan(θ) = XL/R.

Answer is 87.6.

As the formula for phase angle is tan(θ)=XL/R.
θ=tan-1(1100/45)=87.6.
or we can use cos(θ)=R/Z=same answer.
Correct me if I am wrong.

XL/R is for Series, here the question is parallel.

The formula for phase angle in series and parallel is basically the same the only difference it the magnitude.

Arctan θ = -(XL/R) = -87.65739 which is also the same as +2.342612 it just depends on where you measure the angle from it's phase diagram. Since in the choices the given value of 87.6 is positive it would be the incorrect answer since it should be negative. That is why the correct answer is B.