Discussion :: RL Circuits - General Questions (Q.No.3)
What is the true power of a 24 Vac parallel RL circuit when R = 45 and XL = 1100 ?
Answer: Option B
No answer description available for this question.
|Ranjit said: (Sep 2, 2011)|
|No power is dissipated in L...
|Soundarya said: (Sep 27, 2011)|
|There is no dissipation of power at inductor.so
=(24*24)/45=12.8 is the answer
|C.P. Borkar said: (Nov 25, 2011)|
I=V/R =24/45 = O.533
|Hareshwar said: (Jan 20, 2012)|
|Sindhu Priya said: (Aug 27, 2012)|
|Lochana.Vyas said: (Apr 24, 2013)|
|As they said only true power so inductance value will not be there and only purely resistive load is used:-.
V^2/R = (24) ^2/45 = 12.8W.
|Nasim said: (Sep 1, 2013)|
|Please say why there is no power dissipation in the inductor?|
|Arun said: (Oct 29, 2013)|
|Impedance z = 44.9 ohm.
I = V/Z = 0.534 A.
TRUE POWER = V*I*COS(PHI)=12.78 VOLT.
PHI = TAN inv(R/Xl) = 2.34.
|Sudhi. said: (Dec 10, 2014)|
|If there is no losses in the inductor it is simple. This means no equivalent series or parallel are. Use 2pi x f x L to get the reactance, and then the current by ohms law.
There is no power dissipated. Current is drawn but it recirculates without any heating. The inductor charges and discharges.
|Rajan said: (Nov 16, 2016)|
|Another way is total I * V.
There is a power dissipated in the resistor and also low lost in Inductor.
So both need to be considered !
In parallel circuit Total current It= IL +Ir but since they are not in the same phase so cannot plus directly.
It^2 = IL^2 + Ir^2.
Ir = V/R =24/45 = 0.533.
IL = V/Xl =24/1100 = 0.0218.
It = sqr(IL^2 +Ir^2) = sqr(0.5333*0.5333 +0.02182*0.02182) = 0.53345.
It = 0.53345 ampere.
Power = VIt = 24 * 0.5334 = 12.80 (more accurate).
|Priti said: (Apr 9, 2017)|
|Ir=24/45(voltage equal in parallel).
Real power =Ir^2 * 45 = 12.8.
|Pawan said: (Aug 12, 2018)|
|Why is inductive reactance not considered here?
Anyone, please explain.
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