Electronics - RL Circuits - Discussion
Discussion Forum : RL Circuits - General Questions (Q.No. 2)
2.
Calculate the voltage dropped across R1 in the given circuit.
Discussion:
11 comments Page 1 of 2.
Vivek yadav said:
3 years ago
What is the voltage drop across L1? Please explain anyone.
Saran said:
4 years ago
R1 is 10K, then how it will be R1=10^2?
Blank said:
5 years ago
FOR DC VOLTAGE inductor treated as a short circuit?
KIRAN V said:
6 years ago
I think voltage is same at any point in a parallel circuit.
Prasanna kumar said:
7 years ago
Voltage across resistor, R1= Resistance value * Supply voltage/Total resistance.
VR1 = R1*Vs/ (sqrt(R1^2+(2*pi*f*L)^2).
VR1 = 10*27/(sqrt(10^2 + (2*pi*20*10^3*10*10^- 6)^2).
= 26.78V.
VR1 = R1*Vs/ (sqrt(R1^2+(2*pi*f*L)^2).
VR1 = 10*27/(sqrt(10^2 + (2*pi*20*10^3*10*10^- 6)^2).
= 26.78V.
Dipanjan said:
8 years ago
XL1 = 2*pi*f*L=2*3.14*20*10^3*10^-5 = 1.256 ohms.
Z1 = sqrt[(R1^2)+(XL1)^2] = sqrt(10^2+1.256^2) = 10.0786 ohms.
Voltage dropped across R1 = Vs*(R1/Z1) = 27*(10/10.0786) = 26.8 V.
Z1 = sqrt[(R1^2)+(XL1)^2] = sqrt(10^2+1.256^2) = 10.0786 ohms.
Voltage dropped across R1 = Vs*(R1/Z1) = 27*(10/10.0786) = 26.8 V.
Amit kumar sahoo said:
9 years ago
Find REACTANCE XL using XL = 2*pi*f*L.
Find total impedance Z = (R^2+XL^2)^1/2.
Using voltage divider formula find voltage across R.
VOLTAGE ACROSS R = TOTAL VOLTAGE*(R/Z).
Find total impedance Z = (R^2+XL^2)^1/2.
Using voltage divider formula find voltage across R.
VOLTAGE ACROSS R = TOTAL VOLTAGE*(R/Z).
Adeel Awan said:
1 decade ago
XL for L1 => 2*pi*20 000*10x10^-6 = 1.256 ohms
Sqr(R1^2+XL^2) = sqrroot(10^2+1.256^2) = 10.0786 ohms
And use voltage divider Vs(R1/R total) = 27(10/10.0786) = 26.789 V or 26.8 V
Sqr(R1^2+XL^2) = sqrroot(10^2+1.256^2) = 10.0786 ohms
And use voltage divider Vs(R1/R total) = 27(10/10.0786) = 26.789 V or 26.8 V
Sekhar said:
1 decade ago
Please give me the explanation.
Scott said:
1 decade ago
First find XL for L1 => 2*pi*20 000*10x10^-6 = 1.256 ohms
after that find impedance which is sqr(R1^2+XL^2) = sqr(10^2+1.256^2) = 10.0786 ohms
and use voltage divider Vs(R1/R total) = 27(10/10.0786) = 26.789 V or 26.8 V
after that find impedance which is sqr(R1^2+XL^2) = sqr(10^2+1.256^2) = 10.0786 ohms
and use voltage divider Vs(R1/R total) = 27(10/10.0786) = 26.789 V or 26.8 V
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