Electronics - Resistance and Power - Discussion
Discussion Forum : Resistance and Power - General Questions (Q.No. 20)
20.
What happens to current and resistance if the voltage doubles?
Discussion:
5 comments Page 1 of 1.
Dalitso paul said:
9 years ago
Golsh, exactly true.
TAPASREE GHOSH said:
10 years ago
V = IR.
Now 2*v = 2*I*R.
We know that when resistance is high then small amount of current can pass but when resistance is low then high amount of current can pass.
So here as the current will be multiplied by 2 not R. Thus, option D is correct.
Now 2*v = 2*I*R.
We know that when resistance is high then small amount of current can pass but when resistance is low then high amount of current can pass.
So here as the current will be multiplied by 2 not R. Thus, option D is correct.
MANJU said:
1 decade ago
V=IR.
Multiply 2 both side.
2V = 2IR.
Voltage and current varies not resistance.
So,
2V =(2I)R.
Multiply 2 both side.
2V = 2IR.
Voltage and current varies not resistance.
So,
2V =(2I)R.
Hariom said:
1 decade ago
Here R constant but current is variable so current double.
Yogesh said:
1 decade ago
V=IR
I=V/R
I=2V/2R-->V/R
Current remains same while in our case resistance is doubles.
I=V/R
I=2V/2R-->V/R
Current remains same while in our case resistance is doubles.
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