Electronics - RC Circuits - Discussion
Discussion Forum : RC Circuits - Filling the Blanks (Q.No. 1)
1.
The phase angle in the given circuit equals___.
Discussion:
8 comments Page 1 of 1.
Saurav said:
1 decade ago
Can anyone please give me the solution to this problem.
Arpitha said:
1 decade ago
The circuit gives an overall impedance of 30||-j40
ie., (30*-j40)/(30-j40)=-j1200/(30-j40)
Current I=V/R= 120/R
On solving we get I=4+j3
Phase angle = tan inverse of(3/4)=36.86
ie., (30*-j40)/(30-j40)=-j1200/(30-j40)
Current I=V/R= 120/R
On solving we get I=4+j3
Phase angle = tan inverse of(3/4)=36.86
Hasnain said:
1 decade ago
Please elaborate this step : (30*-j40)/(30-j40) = -j1200/(30-j40)?
Karl said:
9 years ago
This is a parallel circuit.
IR = V/R = 120/30 = 4A.
Zeq = 50.
IT = V/Zeq = 120/50 = 2.4A.
Cos theta (for parallel circuit) = IR/IT = 4/2.4.
So, the angle would be cos inverse * 4/2.4.
This does not compute.
IR = V/R = 120/30 = 4A.
Zeq = 50.
IT = V/Zeq = 120/50 = 2.4A.
Cos theta (for parallel circuit) = IR/IT = 4/2.4.
So, the angle would be cos inverse * 4/2.4.
This does not compute.
Abhishek Gowda said:
9 years ago
Active power = v/r = 120/30 = 4A,
Reactive power = v/xc = 120/40 = 3A ,
Aparent power = sqrt (4^2 + 3^2) = 5A,
Angle = cos^-1( 4/5) = 36.87.
Reactive power = v/xc = 120/40 = 3A ,
Aparent power = sqrt (4^2 + 3^2) = 5A,
Angle = cos^-1( 4/5) = 36.87.
Dhanalakshmi said:
8 years ago
Tan' (r/xc) is the formula.
Ilon said:
7 years ago
θ= tan (R/Xc).
Pritam said:
5 years ago
θ= tan-1(wCR).
Xc=1/wC.
wC=1/Xc.
θ= tan-1(R/Xc).
Xc=1/wC.
wC=1/Xc.
θ= tan-1(R/Xc).
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