Electronics - RC Circuits - Discussion
Discussion Forum : RC Circuits - General Questions (Q.No. 8)
8.
What is the phase angle for a parallel circuit consisting of a 500 kHz, 5 Vac source with a 47 pF capacitor, and a 4.7 k
resistor in parallel?
resistor in parallel?Discussion:
10 comments Page 1 of 1.
Mehtab said:
9 years ago
For parallel RC circuit phase angle is nothing but tan inverse (-wXcR). So we will get 34.8°
KEN said:
7 years ago
Always remember that phase angle is referenced at Irms' angle. Try to divide Vrms to Ztotal.
Mehtab said:
9 years ago
They asked to find phase angle for parallel circuit tan^1 (-wXcR) = 34.8°.
Mon said:
1 decade ago
In series RC Theta = tan inv (XC/R).
In Parallel RC Theta = tan inv(R/XC).
In Parallel RC Theta = tan inv(R/XC).
Qwertyuiop said:
8 years ago
It should be -34.8 means voltage is lagging because it has a capacitor.
(1)
Pratik said:
1 decade ago
How is the 34. 8 answer is right ?
What is the formula ?
What is the formula ?
Chandrani said:
1 decade ago
Why arctan(-xc/R)? why shouldn't we do arctan(xc/R)?
Lalu said:
1 decade ago
for parallel circuit tan-1(Ic/Ir)
Ic=V/Xc
Ir= V/R
Ic=V/Xc
Ir= V/R
Amrut said:
1 decade ago
Calculate xc then tan inverse (-xc/R).
Shekh said:
7 years ago
The ans will be -34.8.
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