Electronics - RC Circuits - Discussion
Discussion Forum : RC Circuits - General Questions (Q.No. 11)
11.
What is the current through XC1 in the given circuit?
Discussion:
10 comments Page 1 of 1.
Scorpius said:
4 years ago
Here, we have to find the total circuit current.
R1 and C1 are in series connection with each other, therefore the current passing through those components are the same, and that current is the circuit current because it has not yet branched out as it has not passed through any node.
R1 and C1 are in series connection with each other, therefore the current passing through those components are the same, and that current is the circuit current because it has not yet branched out as it has not passed through any node.
Manasvi said:
4 years ago
Exactly right @Aman.
Maybe they have considered Xc2 as an inductor, with +250j impedance instead of -250j.
Maybe they have considered Xc2 as an inductor, with +250j impedance instead of -250j.
Aman said:
5 years ago
The answer should be 20mA.
Tashi said:
6 years ago
@Alberr.
I don't understand why you're ignoring the components of parallel branches. Please, somebody, help me to find the total impedance of the given circuit in details.
I don't understand why you're ignoring the components of parallel branches. Please, somebody, help me to find the total impedance of the given circuit in details.
Alberr said:
6 years ago
180-240j, it's in series.
then, 10/180-240j.
And get 0.0333 or 33.3mA.
Approximately to 32.2mA.
then, 10/180-240j.
And get 0.0333 or 33.3mA.
Approximately to 32.2mA.
Riego said:
7 years ago
Why can't we use XC2 as an inductive load?
Riego said:
7 years ago
Why can't we use XC2 as an inductive load?
(1)
Dong69 said:
7 years ago
@All.
Try recalculating the circuit but this time, instead of XC1, replace it with an inductor, having an impedance of +240j. You will get the answer 32.2 mA.
Try recalculating the circuit but this time, instead of XC1, replace it with an inductor, having an impedance of +240j. You will get the answer 32.2 mA.
Qadeem kakar said:
9 years ago
Zt = 332.2.
I = v/z = 0.0301.
=> 30.123m Approximately 32.
I = v/z = 0.0301.
=> 30.123m Approximately 32.
Ajaykumar prasad said:
1 decade ago
Since (333 II 250) = ri.
ri+180+240 = 560.
10/560 = 0.0177.
0.0177*180 = 3.19 v.
10-3.19 = 6.80 v to xc1.
6.80v/240 = 28.3 m approximately 32.
ri+180+240 = 560.
10/560 = 0.0177.
0.0177*180 = 3.19 v.
10-3.19 = 6.80 v to xc1.
6.80v/240 = 28.3 m approximately 32.
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