Electronics - RC Circuits - Discussion

Discussion Forum : RC Circuits - General Questions (Q.No. 3)
3.

What is the voltage drop across R1 in the given circuit?

10 V
4.80 V
4.00 V
5.80 V
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
20 comments Page 1 of 2.

Raja said:   1 decade ago
R2 ll 250i +240i + 180.

Here voltage divides.

Ramkumar said:   1 decade ago
Please explain briefly? I don't understand.

Ajayvignesh said:   1 decade ago
Raja you are wrong. R2 is not parallel to summation of all three. its parallel to only XC2. Hence parallel reistance is 142.8Ohm. Hence drop across 142.8 (equivalanet resistance of 333Ohm and XC2 250Ohm) is

Ajay said:   1 decade ago
Its very easy raja your absolutly correct. This is very basic.

Shahid said:   1 decade ago
Hey friends let me explain.
For rc SERIES circuit Z=Sqrt of R^2+xC^2
R2 is parallel to 250 so it will be 142.79
It is in series with 180 so total res Rt will be 322.79
Now use formula=z=sqrt(322.79^2+240^2)=402.23
Now we have I=V/Z=0.0248
Now vtg drop across r1=0.024*(180/180+240)=5.78v

Farhan said:   1 decade ago
@Shahid.

You are doing totally wrong, Now you see your step where you find the voltage drop across R1 you use current divider formula that's wrong applied. You use voltage divider instead of current divider.

Vdrop_R10= (R10) *VSupply /Total Resistance of the circuit.

Jay said:   1 decade ago
Here,
I = V/Req.
Req. = R1+XC1+R2 parallel with XC2.

Voltage across R1 is = I*R1.

Scott said:   1 decade ago
I = V/Req.
Zt = R1+XC1+R2 parallel with XC2.
Zt = 500 ohm @ -53.1 degrees.
It = 10v/500 ohm @ -53.1 degrees = 20 mA @ 53.1 degrees.
Vr1 = 180 ohms @ 0 degrees * 20 mA @ 53.1 degrees = 3.6 V @ 53.1 degrees.

ARCHANA SASIKUMAR said:   1 decade ago
R2||XC2 = 142.79 OHM.
XC1+(R2||XC2) = 382.79 OHM.
V1 = 10*(180/180+382.79)V.

Balram said:   1 decade ago
Please provide calculation step by step with logic and formula applied.


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