Electronics - RC Circuits - Discussion
Discussion Forum : RC Circuits - General Questions (Q.No. 6)
6.
Calculate the magnitude of the impedance in the given circuit.
24.1 M
10 M
26.1 M
0
Discussion:
3 comments Page 1 of 1.
Manasa said:
9 years ago
Can we do the same problem by using Laplace?
Like.
Z = R + (1/CS).
Z = 10M + (1/S*0.33 p).
But I struck at converting from s-domain to normal form. Please help me.
Like.
Z = R + (1/CS).
Z = 10M + (1/S*0.33 p).
But I struck at converting from s-domain to normal form. Please help me.
Savitha U.R said:
1 decade ago
Impedence Z=square root(R^2+Xc^2)
Xc=1/(2*pi*f*c)=1/(2*3.14*20*10^3*0.33*10^-12)
=1/(6.28*20*0.33)*(10^3-12)
=(1/41.448)*10^9
=0.0241*10^9
Xc=24.12*10^6=24.12Mohm
Z=Square root(R^2+Xc^2)
=Square root[(10*10^6)^2+(24.12*10^6)^2]
=Square root[(10)^2+(24.12)^2*(10^6)^2]
=Square root[100+582.0928*(10^6)^2]
=Square root[682.0928*(10^6)^2]
=26.11*10^6=26.1Mohm
Xc=1/(2*pi*f*c)=1/(2*3.14*20*10^3*0.33*10^-12)
=1/(6.28*20*0.33)*(10^3-12)
=(1/41.448)*10^9
=0.0241*10^9
Xc=24.12*10^6=24.12Mohm
Z=Square root(R^2+Xc^2)
=Square root[(10*10^6)^2+(24.12*10^6)^2]
=Square root[(10)^2+(24.12)^2*(10^6)^2]
=Square root[100+582.0928*(10^6)^2]
=Square root[682.0928*(10^6)^2]
=26.11*10^6=26.1Mohm
Rak said:
1 decade ago
z=r-j/wc
z=26M ay angle =-67
z=26M ay angle =-67
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