Electronics - Quantities and Units - Discussion
Discussion Forum : Quantities and Units - General Questions (Q.No. 15)
15.
Add 21 mA and 8000 
A and express the result in milliamperes.
A and express the result in milliamperes.Discussion:
5 comments Page 1 of 1.
Dedipya said:
10 years ago
= 21*10^-3+8*10^3*10^-6.
= 21*10^-3+8*10^-3.
= 10^-3(21+8) = 29 mA.
= 21*10^-3+8*10^-3.
= 10^-3(21+8) = 29 mA.
Subhani said:
1 decade ago
21*10^-3=21mA.
8000*10^-6=8000*10^-3 mA.
Now we can write.
8*10^3*10^-3mA=8mA.
Now;.
21mA+8mA=29mA.
8000*10^-6=8000*10^-3 mA.
Now we can write.
8*10^3*10^-3mA=8mA.
Now;.
21mA+8mA=29mA.
Vijay kumar said:
1 decade ago
Since 1micro=10ka power-6.
8000microamp= (8000*10ka power-6) amp.
Again 1amp= (10ka power3) milliamp.
After solving we get 8 milliamp.
Final result= (21+8) milliamp.
=29 milliamp.
8000microamp= (8000*10ka power-6) amp.
Again 1amp= (10ka power3) milliamp.
After solving we get 8 milliamp.
Final result= (21+8) milliamp.
=29 milliamp.
Savitha u r said:
1 decade ago
21*10^-3+8000*10^-6=21*10^-3+8*1000*10^-6
=21*10^-3+8*10^3*(10^-3*10^-3)
=21*10^-3+8*(10^3-3-3)
=21*10^-3+8*10^-3
=(21+8)10^-3
=29*10^-3
=29mA
=21*10^-3+8*10^3*(10^-3*10^-3)
=21*10^-3+8*(10^3-3-3)
=21*10^-3+8*10^-3
=(21+8)10^-3
=29*10^-3
=29mA
Parimala said:
1 decade ago
21mA + 8mA = 29mA
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