### Discussion :: Parallel Circuits - General Questions (Q.No.5)

Raji said: (Dec 24, 2010) | |

We know that if voltage increases, current increases & if resistor increase then current decreases.. then in parallel current ckt as increases total resistance also increases... |

S.Jeyasudha said: (Jun 13, 2011) | |

According to the parallel resistance circuit the equivalent resistance is given by RT=R1||R2= (R1*R2)/(R2+R2. That answer will be less compare with when any one resistance open, because the total resistance is equalto RT=R1 or R2 only. So RT is increases. |

Aditya said: (Jul 13, 2011) | |

If we consider the two resistance in parallel, r1 &r2, So according law R1*R2/ (R1+R2). If one of them is open means R1=NO, So it will be R2 in Series. So total resistance will decrease. |

Ankit said: (Aug 1, 2011) | |

As we know for a particular resistor in series net resistance is greater than a resistance in parallel if we remove resistor of one of them from a parallel circuit the net result will increases as reverse as in series. |

Nandini said: (Oct 30, 2011) | |

Can you give me the proper explanation? I want correct answer. |

Ragi G R said: (Jan 11, 2012) | |

In parallel resistance the effective resistance value will be less than the smallest valued resistance. For eg, if a 2 ohm and 3 ohm resistance are in parallel effective resistance will be less than 2 ohm. So when one is opened the effective resistance increases. |

Sreeyush Sudhakaran said: (Feb 19, 2012) | |

Case 1: R1&R2 in parallel RT=(R1XR2)/(R1+R2) Case 2 : R2 is open circuited RT= R1 To understand correctly case 1: R1=1k R2=1k RT= (1x10^6)/(2x10^3) RT= 0.5k case 2: R1=1k RT=1k So RT increases with removal of R2 |

Matthew said: (May 4, 2012) | |

Consider two resistors in parallel. Their total resistance is, (R1 * R2) / (R1 + R2) We would like to determine the effect of opening R2. The circuit then contains a single resistor, R1 in series. We would then like to determine whether ? is > or < in the below equation, (R1 * R2) / (R1 + R2) ? R1 Let's multiply both sides of this inequality by (R1 + R2), which yields, R1 * R2 ? R1 * (R1 + R2) expanding the right hand side yields, R1 * R2 ? R1^2 + R1 * R2 Since resistance is always positive, we have that the right hand side is larger. Therefore, we conclude that resistance will increase. |

Prasanna said: (Aug 19, 2012) | |

Let me explain with the example Let R1 = 4 & R2 =4 Then RT = R1* R2/( R1+R2) =4*4/4+4 =16/8 =2 ohms If R1 is open then R1= not available So RT = R2 =4 That means total resistance increases as one of the resistance is opened. |

Subrata said: (Feb 20, 2013) | |

What will be answered if more than two resistance is connected in a circuit? Like, r1=2, r2=3, r3=4. |

Sushil said: (May 3, 2013) | |

In series voltage is constant therefore in the circuit only changes current ane of the fact is that resistance decreases then current also increases as per ohms law. |

Roshan said: (Oct 11, 2013) | |

As circuit is open no current flows & infinite resistance. |

BHARGAVI VEERA said: (Nov 30, 2013) | |

Same question in series then then total resistance what happen? |

Abc said: (Feb 5, 2014) | |

If one of the resistors that are connected in series is opened, then total resistance becomes infinite. |

Spurthi said: (Oct 4, 2014) | |

If any one of the resistor connected in parallel is open can we take that resistor value as 0? |

Ravi said: (Dec 19, 2014) | |

Take V = IR relation. In parallel circuit voltage is constant. So IR must be a constant value if one terminal is open means I = 0. So R became infinity. |

Keerthi Raj said: (Feb 3, 2015) | |

Suppose if you have more than 2 resistors say r1=r2=r3=2 ohm then the equivalent resistance is around 1.3 ohm. Say r3 is opened then the equivalent resistance is 1 ohm hence from this the resistance is decreased. If we consider only 2 resistors in parallel then the resistance will be increased. |

Azhagusurya said: (Feb 20, 2015) | |

Consider r1 ,r2 are the resistance which are in parallel. If any one of resistor get open mean the connection became series. Ex: r1 = 2kohm. r2 = 1kohm. If both are in parallel means Rt = r1*r2/(r1+r2) = 2/3 = 0.667 kohm. If both are in series means, Rt = r1+r2. Rt = 2+1 = 3kohm. So resistance value increases when one of them get opened. |

Vicky Meena said: (Mar 10, 2015) | |

How many resistor is there? |

Vicky said: (Oct 11, 2015) | |

What happens to total resistance in a circuit with parallel resistors if one of them opens? Anyone explain this question please? |

MITHUN said: (Oct 13, 2015) | |

No. The given answer is wrong. It may increase or decrease resistance value depending on the value of resistance. |

Sooraj said: (Aug 9, 2016) | |

If R1 is in series with parallel connected to R2 and R3, what happens to total current if R2 opens? |

Shandelin Priyanka said: (Jun 11, 2017) | |

Three identical resistors are connected in series to a battery. If the current of 12 A flows the battery, how much current flows through any one of the resistors? Can anyone answer this? |

Tushar said: (Jun 15, 2019) | |

If one of the resistors in a parallel circuit, is removed, what happens to the total resistance? |

Syed Shakeeb said: (Jun 4, 2022) | |

In a parallel circuit, if any one resistor remains open the total circuit resistance increases. |

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