Electronics - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 4)
4.
What is the total power loss if 2 k
and 1 k parallel-connected resistors have an IT of 3 mA?
and 1 k parallel-connected resistors have an IT of 3 mA?6 
W
W36 W
W6 mW
36 mW
Discussion:
39 comments Page 1 of 4.
Sudhakar said:
1 decade ago
Here total current given is It=3mamp,
And R1=2kohm, R2=1kohm are in parallel,
So equivalent resistance of 2 parallel resistors is Req=R1*R2/ (R1+R2).
So Req=2kohm*1kohm/ (2kohm+1kohm).
= (2*1*kohm*kohm) / (3kohm).
=2kohm/3.
Now total power loss in a circuit is=It^2 (Req).
= (3mamp*3mamp) (2kohm/3) =6mw is the correct answer.
And R1=2kohm, R2=1kohm are in parallel,
So equivalent resistance of 2 parallel resistors is Req=R1*R2/ (R1+R2).
So Req=2kohm*1kohm/ (2kohm+1kohm).
= (2*1*kohm*kohm) / (3kohm).
=2kohm/3.
Now total power loss in a circuit is=It^2 (Req).
= (3mamp*3mamp) (2kohm/3) =6mw is the correct answer.
Addy said:
9 years ago
Simply,
Low resistance = Higher current flow.
So, we get applied voltage by dividing current in the ratio
2k/1k = 3mA.
1k = 2mA and 2k = 1mA.
Hence, applied voltage is 2V.
Now, we have I = 3mA, V = 2v.
P = V * I.
= 2 * 3mA.
= 6mA.
ANSWER 'C' IS CORRECT.
Low resistance = Higher current flow.
So, we get applied voltage by dividing current in the ratio
2k/1k = 3mA.
1k = 2mA and 2k = 1mA.
Hence, applied voltage is 2V.
Now, we have I = 3mA, V = 2v.
P = V * I.
= 2 * 3mA.
= 6mA.
ANSWER 'C' IS CORRECT.
Sameer said:
7 years ago
Power=Voltage * Current.
Voltage= Current * Resistance,
Resistors in parallel (1/R=1/R1+1/R2) OR (R=R1*R2/R1+R2),
so, 1/R= 1/2+1/1 = 3/2KOhm , R= 2/3 KOhm,
P=V*I = (I*R)* I.
P= I*I*R,
P=3*3*2/3,
P=9*2/3,
P=18/3,
P=6mW.
Voltage= Current * Resistance,
Resistors in parallel (1/R=1/R1+1/R2) OR (R=R1*R2/R1+R2),
so, 1/R= 1/2+1/1 = 3/2KOhm , R= 2/3 KOhm,
P=V*I = (I*R)* I.
P= I*I*R,
P=3*3*2/3,
P=9*2/3,
P=18/3,
P=6mW.
Rashmi said:
1 decade ago
V = IR BY OHM'S LAW.
From the following data:
I = 3 m.
R1 = 1k.
R2 = 2k.
When resistors are connected in parallel.
Req is given by Req = R1*R2/R1+R2.
P = I^2*Req.
P = (3m)^2*(2/3)k.
P = 6 mW.
From the following data:
I = 3 m.
R1 = 1k.
R2 = 2k.
When resistors are connected in parallel.
Req is given by Req = R1*R2/R1+R2.
P = I^2*Req.
P = (3m)^2*(2/3)k.
P = 6 mW.
(1)
Hims said:
1 decade ago
Rp = 2*1/2+1 = 2/3 kohm = (2/3) * 10^3 ohm.
P = i2*r.
i = 3mA = 3*10^-3A.
P = (3*10^-3)A*(3*10^-3)A* (2/3)* 10^3 ohm.
P = (3*3*2/3)W * (10^-3*10^-3*10^3).
P = (6)W*(10^-3) = 6*10^-3W.
P = 6mW.
P = i2*r.
i = 3mA = 3*10^-3A.
P = (3*10^-3)A*(3*10^-3)A* (2/3)* 10^3 ohm.
P = (3*3*2/3)W * (10^-3*10^-3*10^3).
P = (6)W*(10^-3) = 6*10^-3W.
P = 6mW.
Sunil Kumar said:
1 decade ago
Parallel Connection
Req = R1*R2/R1+R2.
Req = 2000*1000/2000+1000
= (2000/3000) ohms i.e (2/3)K ohms.
P = I^2 * Req.
= (3*10^-3)^2 * (2/3) * 10^3
= 9 * 10^-6 * (2/3) * 10^3
= 6 m Watts
Req = R1*R2/R1+R2.
Req = 2000*1000/2000+1000
= (2000/3000) ohms i.e (2/3)K ohms.
P = I^2 * Req.
= (3*10^-3)^2 * (2/3) * 10^3
= 9 * 10^-6 * (2/3) * 10^3
= 6 m Watts
Vinay said:
1 decade ago
Current will divide as 2mA in 1K and 1mA in 2k resistors
so power is given by p=i^2*R
power at 2k=1^2*2
=2mw
|||'y at 1k=2^2*1
=4mw
Total power=2mw+4mw
=6mw
so power is given by p=i^2*R
power at 2k=1^2*2
=2mw
|||'y at 1k=2^2*1
=4mw
Total power=2mw+4mw
=6mw
Divya said:
9 years ago
P = VI -----> 1.
V = IR -----> 2.
Substitute above equation in 1,
We get P = I^2 * R.
R = 2*1/2 + 1,
R = 2/3,
P = (3*10^-3)^2*(2/3)*10^3 ohm,
p = 6mW.
V = IR -----> 2.
Substitute above equation in 1,
We get P = I^2 * R.
R = 2*1/2 + 1,
R = 2/3,
P = (3*10^-3)^2*(2/3)*10^3 ohm,
p = 6mW.
Chandu said:
1 decade ago
PARALLEL CONNECTION:-
R eq =
[(2 X 1) (10^3 X 10^3)]/[(2+1) 10^3]
2/3 10^3 OHMS..........
P= I * I * R eq
(3*3*2/3)(10^-3)(10^-3)(10^3)
6mw ans
R eq =
[(2 X 1) (10^3 X 10^3)]/[(2+1) 10^3]
2/3 10^3 OHMS..........
P= I * I * R eq
(3*3*2/3)(10^-3)(10^-3)(10^3)
6mw ans
Ramprabu said:
1 decade ago
P=I^2(R)
R=>2K AND 1K IN PARALLEL
HENCE EQUALENT R VALUE IS (2/3)
P=(3m)^2(2/3)
=>(9u)(2/3)
=>6uw
SO I CONCLUDE HERE OPTION A IS CORRECT
R=>2K AND 1K IN PARALLEL
HENCE EQUALENT R VALUE IS (2/3)
P=(3m)^2(2/3)
=>(9u)(2/3)
=>6uw
SO I CONCLUDE HERE OPTION A IS CORRECT
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