Electronics - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 38)
38.
What is RT for fifteen 2 M
resistors all connected in parallel?
resistors all connected in parallel?133 k
300 k
750 k
30 M
Discussion:
10 comments Page 1 of 1.
Abhay partap singh rana said:
2 years ago
Solution:
r(eq) = r/n.
= 2/15 = 0.133 m ohm = 133k Ω.
r(eq) = r/n.
= 2/15 = 0.133 m ohm = 133k Ω.
Swathi said:
4 years ago
Thanks @Ajay.
Amol said:
4 years ago
Thanks all for explaining the answer.
Huma said:
5 years ago
Thanks @Ajay.
Aditya akolkar said:
5 years ago
Good one, Thanks @Ajay.
Sandeep gupta said:
5 years ago
Thanks for the easy calculation @Ajay Singh.
Sagar said:
6 years ago
Thanks for easy calculation @Ajay.
Ajay Singh(Himachal) said:
10 years ago
We know that.
1/RT = 1/R1+1/R2+1/R3.......1/Rn.
Then RT for fifteen 2 Mohm
1/RT = 1/R1+1/R2+1/R3.......1/R15
Here R1=R2=R3=......R15 = 2.
Therefore 1/RT = 1/2+1/2+1/2+....1/2(for fifteen time).
Take common 1/2.
Now 1/RT = 1/2(1+1+1+1+1....1(for fifteen time).
1/RT = 1/2(15) = 15/2.
Therefore RT = 2/15 = 0.133Mohm.
Now convert Mohm into kohm.
So Ans. 133 kohm.
1/RT = 1/R1+1/R2+1/R3.......1/Rn.
Then RT for fifteen 2 Mohm
1/RT = 1/R1+1/R2+1/R3.......1/R15
Here R1=R2=R3=......R15 = 2.
Therefore 1/RT = 1/2+1/2+1/2+....1/2(for fifteen time).
Take common 1/2.
Now 1/RT = 1/2(1+1+1+1+1....1(for fifteen time).
1/RT = 1/2(15) = 15/2.
Therefore RT = 2/15 = 0.133Mohm.
Now convert Mohm into kohm.
So Ans. 133 kohm.
Varn said:
1 decade ago
1/RT = 15/(2*10^6)
i.e RT=2*10^6/15
RT=133K
i.e RT=2*10^6/15
RT=133K
Seshendra said:
1 decade ago
if n resistors each of value R are connected in parellel then equivalant resistance ic R/n...
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