# Electronics - Parallel Circuits - Discussion

Discussion Forum : Parallel Circuits - General Questions (Q.No. 38)
38.
What is RT for fifteen 2 M resistors all connected in parallel?
133 k 300 k 750 k 30 M Explanation:
No answer description is available. Let's discuss.
Discussion:
10 comments Page 1 of 1.

Abhay partap singh rana said:   2 years ago
Solution:

r(eq) = r/n.
= 2/15 = 0.133 m ohm = 133k Ω.

Swathi said:   4 years ago
Thanks @Ajay.

Amol said:   4 years ago
Thanks all for explaining the answer.

Huma said:   5 years ago
Thanks @Ajay.

Aditya akolkar said:   5 years ago
Good one, Thanks @Ajay.

Sandeep gupta said:   5 years ago
Thanks for the easy calculation @Ajay Singh.

Sagar said:   6 years ago
Thanks for easy calculation @Ajay.

Ajay Singh(Himachal) said:   10 years ago
We know that.

1/RT = 1/R1+1/R2+1/R3.......1/Rn.

Then RT for fifteen 2 Mohm

1/RT = 1/R1+1/R2+1/R3.......1/R15

Here R1=R2=R3=......R15 = 2.

Therefore 1/RT = 1/2+1/2+1/2+....1/2(for fifteen time).
Take common 1/2.

Now 1/RT = 1/2(1+1+1+1+1....1(for fifteen time).

1/RT = 1/2(15) = 15/2.

Therefore RT = 2/15 = 0.133Mohm.

Now convert Mohm into kohm.

So Ans. 133 kohm.