Electronics - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - Filling the Blanks (Q.No. 9)
9.
The total power in the given circuit is ___.
Discussion:
2 comments Page 1 of 1.
Jazz said:
8 years ago
1/Rt=1/20+1/8+1/30.
=5/24
Rt=24/5
I= V/R
12*5/24=5/2.
P=VI.
=12*5/2,
=30mW.
=5/24
Rt=24/5
I= V/R
12*5/24=5/2.
P=VI.
=12*5/2,
=30mW.
@nusha said:
1 decade ago
p = vi.
v = i*r therefore p=(v^2)/r.
Total resistance = (1/20k)+(1/8k)+(1/30k) = 4.8k ohm.
p = (12*12)/(4.8K) = 30mW.
v = i*r therefore p=(v^2)/r.
Total resistance = (1/20k)+(1/8k)+(1/30k) = 4.8k ohm.
p = (12*12)/(4.8K) = 30mW.
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