Electronics - Parallel Circuits - Discussion

11. 

If R1 opens in the given circuit, the total current equals ___.

[A]. 86 mA
[B]. 170 mA
[C]. 42 mA
[D]. 128 mA

Answer: Option D

Explanation:

No answer description available for this question.

Govind said: (Sep 22, 2011)  
According to kcl law I=I1+I2;.

Whn open i1=0; hence total current is 128mA.

Smiley said: (Aug 17, 2013)  
But when i1 is open then total current will flow through R2 so it should be 170 isn't it ?

Vignesh said: (Jul 30, 2014)  
Yes I have same doubt, But when i1 is open then total current will flow through R2 so it should be 170 isn't it ?

Naisy said: (Sep 16, 2015)  
I don't understand the reason the correct answer is 128 mA, since I1 is closed, meaning the total current will flow to I2 which makes it 170 mA. IT = I1+I2 and if I1 is closed IT = I2.

Siddharth said: (Jan 10, 2016)  
The current flow across the resister depends on the value of the individual resister when they connected in parallel assume r1 as 1 ohm.

And r2 as 1 ohm and and we as 1V than Rt will be 0.5 ohm. It will be 2A, so if r2 removed then It = 1V \r1 = 1v/1ohm = 1A.

So according to ohms law the current flow across r1 is 1A only even though total circuit current is 2A. So when n resisters connected in parallel current flow depends on the value of resister only.

Dra said: (Apr 1, 2016)  
Need resistance for current to flow, if it is open the current cannot flow through the open resistor.

Waheed Ktk said: (Nov 8, 2016)  
The Correct option is 170 A because the whole current will pass through R2.

Abhas said: (Aug 10, 2017)  
Current always flow through minimum resistance path 170mA.

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