Discussion :: Parallel Circuits - Filling the Blanks (Q.No.11)
If R1 opens in the given circuit, the total current equals ___.
Answer: Option D
No answer description available for this question.
|Govind said: (Sep 22, 2011)|
|According to kcl law I=I1+I2;.
Whn open i1=0; hence total current is 128mA.
|Smiley said: (Aug 17, 2013)|
|But when i1 is open then total current will flow through R2 so it should be 170 isn't it ?|
|Vignesh said: (Jul 30, 2014)|
|Yes I have same doubt, But when i1 is open then total current will flow through R2 so it should be 170 isn't it ?|
|Naisy said: (Sep 16, 2015)|
|I don't understand the reason the correct answer is 128 mA, since I1 is closed, meaning the total current will flow to I2 which makes it 170 mA. IT = I1+I2 and if I1 is closed IT = I2.|
|Siddharth said: (Jan 10, 2016)|
|The current flow across the resister depends on the value of the individual resister when they connected in parallel assume r1 as 1 ohm.
And r2 as 1 ohm and and we as 1V than Rt will be 0.5 ohm. It will be 2A, so if r2 removed then It = 1V \r1 = 1v/1ohm = 1A.
So according to ohms law the current flow across r1 is 1A only even though total circuit current is 2A. So when n resisters connected in parallel current flow depends on the value of resister only.
|Dra said: (Apr 1, 2016)|
|Need resistance for current to flow, if it is open the current cannot flow through the open resistor.|
|Waheed Ktk said: (Nov 8, 2016)|
|The Correct option is 170 A because the whole current will pass through R2.|
|Abhas said: (Aug 10, 2017)|
|Current always flow through minimum resistance path 170mA.|
Post your comments here:
Email : (optional)
» Your comments will be displayed only after manual approval.