Electronics - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 18)
18.
What does I3 equal in the given circuit?
Discussion:
8 comments Page 1 of 1.
Sowmya said:
1 decade ago
how it comes can u explain anyone...
Naren said:
1 decade ago
i=v/r
i3= 9/1.8*10^3
i3= 5*10^-3
i3 = 5ma
i3= 9/1.8*10^3
i3= 5*10^-3
i3 = 5ma
Ramesh said:
1 decade ago
Apply ohm law...simple one
Babu MP said:
1 decade ago
Ohm's law I=V/R.
Here I=?
V=9V.
R=1.8X103.
So I=V/R
= 9/18000
=.0005amps=5mA.
Here I=?
V=9V.
R=1.8X103.
So I=V/R
= 9/18000
=.0005amps=5mA.
CHINNU said:
1 decade ago
I3 = V3/R3.
I3 = 9/1.8K.
I3 = 5*10^-3.
= 5mA.
I3 = 9/1.8K.
I3 = 5*10^-3.
= 5mA.
Aastha said:
1 decade ago
I = V/R (by ohm's law)
= 9/1.8
= 90/18
= 5mA.
= 9/1.8
= 90/18
= 5mA.
(1)
Soni said:
10 years ago
At the v = I*r.
I = v/r.
I = 9/1.8 = 5 because the circuit is parallel.
I = v/r.
I = 9/1.8 = 5 because the circuit is parallel.
(1)
Pre said:
9 years ago
i3 = v3/r3.
=> 9/1.8.
=> 1/0.2.
=> 1/2 * 10^(-1).
=> 1 * 10/2.
=> 10/2.
=> 5.
=> 9/1.8.
=> 1/0.2.
=> 1/2 * 10^(-1).
=> 1 * 10/2.
=> 10/2.
=> 5.
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