Electronics - Operational Amplifiers - Discussion
Discussion Forum : Operational Amplifiers - General Questions (Q.No. 46)
46.
A differential amplifier has a common-mode gain of 0.2 and a common-mode rejection ratio of 3250. What would the output voltage be if the single-ended input voltage was 7 mV rms?
Discussion:
11 comments Page 1 of 2.
A Dsilva said:
4 years ago
CMRR = Ad/Acm.
3250 = Ad/0.2,
Ad = 650.
Ad = Vo/Vin.
Vo = 650x 7x 10^-3,
= 4.55V rms.
3250 = Ad/0.2,
Ad = 650.
Ad = Vo/Vin.
Vo = 650x 7x 10^-3,
= 4.55V rms.
(3)
Pranali Navale said:
5 years ago
Given,
CMRR = 3250 Acm = 0.2 Vin = 7mVRMS
CMRR = Ad/Acm : Ad = CMRR*Acm.
Therefore, Ad= 3250*0.2=650.
Now, Vout = Ad * Vin = 650 * 7 * 10^-3 = 4.55VRMS.
CMRR = 3250 Acm = 0.2 Vin = 7mVRMS
CMRR = Ad/Acm : Ad = CMRR*Acm.
Therefore, Ad= 3250*0.2=650.
Now, Vout = Ad * Vin = 650 * 7 * 10^-3 = 4.55VRMS.
(2)
Syed Shakeeb said:
3 years ago
Ad = CMRR*Acm.
Vout = Vin*Ad.
Vout = Vin*Ad.
(1)
Sujata said:
1 decade ago
CMRR=Ad/Acm
Vout=Vin*Ad
Vout=Vin*Ad
Prabhu said:
1 decade ago
Hi.. What's this "A" in
CMRR=Ad/Acm??
Could you plz explain it??
CMRR=Ad/Acm??
Could you plz explain it??
Pondri said:
1 decade ago
Ad represents the differential mode gain and ac represents common mode gain.
Gokul said:
1 decade ago
'A' represents gain
Vpsingh said:
1 decade ago
From, CMRR= A(DIFF. MODE GAIN)/A(COMMON MODE GAIN).
A(DMG)==.2*3250
==650,
V(OUT)==650*7MV
==4.55VRMS
A(DMG)==.2*3250
==650,
V(OUT)==650*7MV
==4.55VRMS
Pavas said:
1 decade ago
Thanks sujata.
Abhi said:
6 years ago
How do we know it is inverting or non inventing for using gain formula? Please, anyone, explain me.
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