Electronics - Operational Amplifiers - Discussion
Discussion Forum : Operational Amplifiers - True or False (Q.No. 26)
26.
If the frequency of an astable multivibrator is 54.86 kHz then its period is 1.82 s.
Discussion:
2 comments Page 1 of 1.
KIRAN V said:
5 years ago
f = 1 /T ==> 1/(54.86 * 10^3).
f = 1.82 s.
f = 1.82 s.
Shruti said:
9 years ago
F = 1/T = 1.44/((RA + RB * 2) * C).
Answer is 18.2.
Answer is 18.2.
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