Electronics - Operational Amplifiers - Discussion

Yes the output of integrator is triangle wave.

Simply we can say that the circuit given is "Miller integrator" so obviously the output will be a triangular wave.

Since it is integrator it output is triangle wave.

Yes the o/p of a low pass filter it means that integrator is a triangle.

The o/p of a low pass filter i.e. integrator is a triangle.

So according to given above statement, input must be need to desire the output of the integrator

when sine input --------> co(sine) output

when dc input-------> ramp output(squar wave---> triangular wave)

If the input voltage is zero, no input current will flow. Therefore no feedback current can flow and the output voltage will remain constant. If the input voltage is non-zero, the basic equation for the output voltage becomes Vout = -Vin/RC + K, where R is the input resistance in ohms, C is the feedback capacitance in farads, and K is a fixed constant representing the accumulated voltage from the past.

If the input voltage is constantly changing, the output voltage at any instant will be the integral of all past input voltage values. For example, a bipolar sine wave input will actually produce another sine wave as its output, at a phase angle of 90° from the input sine wave. Technically, the output will be an inverted cosine wave.

If the input is a constant positive dc voltage, the output will be a negative linear ramp. There is no exponential factor in an op amp integrator. The equation for the ramp will be Vout = -Vint/RC, where t is time in seconds.

What ever the signal it may be, due to capacitor charging and discharging the o/p waveform will come almost triangular.

Input required.

Yes, the data is insufficient.