Electronics - Operational Amplifiers - Discussion
Discussion Forum : Operational Amplifiers - General Questions (Q.No. 22)
22.
What is the output voltage?
Discussion:
10 comments Page 1 of 1.
Habtamu said:
4 years ago
Water in a glass with a volume of 20ml mixed with 80grams of sugar and heated to 80c. How many grams of sugar dissolved in a liquid solution at a temperature of 80c? Express the result in grams.
Can anyone answer this?
Can anyone answer this?
Hemalatha. G said:
6 years ago
Vout = -(Rf÷Rin)*Vin =-(10k÷1k)*500m = -5v.
Deepa gundlur said:
8 years ago
Given r2=10k, r1=1k, vin=500m.
We know that v0= vin (-r2/r1),
= 500m(-10k/1k),
= -5v.
We know that v0= vin (-r2/r1),
= 500m(-10k/1k),
= -5v.
(1)
JEHAD said:
1 decade ago
The voltage gain for inverting op-amp = -Rf/Rin...........(1).
The voltage gain also is Vout/Vin ............(2).
NOW (1) = (2).
-10Kohm/1Kohm = Vout/500m, So, Vout = - 500mv*(10) = - 5000mv = -5v.
The minus sign indicate that the output signal is inverted.
The voltage gain also is Vout/Vin ............(2).
NOW (1) = (2).
-10Kohm/1Kohm = Vout/500m, So, Vout = - 500mv*(10) = - 5000mv = -5v.
The minus sign indicate that the output signal is inverted.
Apoorva said:
1 decade ago
As it is inverting amplifier so output voltage will be
vo=-vin(Rf/Rin).
Given vin=500mv, Rf=10Kohm, Rin=1Kohm
= -500mv(10/1)
= -5000mv
= -5v.
vo=-vin(Rf/Rin).
Given vin=500mv, Rf=10Kohm, Rin=1Kohm
= -500mv(10/1)
= -5000mv
= -5v.
Dinesh sharma said:
1 decade ago
Rf = 10kohm; R1 = 1kohm; Vin = 500mv;
We know that Vout = Vin(-Rf/R1);
= 500m(-10k/1k)
= -5v
We know that Vout = Vin(-Rf/R1);
= 500m(-10k/1k)
= -5v
Kumar said:
1 decade ago
It is a virtual ground because the 1 pin is connected to ground. So
Rf = 10kohm; R1 = 1kohm; Vin = 500mv;
We know that Vout = Vin(-Rf/R1);
= 500m(-10k/1k)
= -5v
Rf = 10kohm; R1 = 1kohm; Vin = 500mv;
We know that Vout = Vin(-Rf/R1);
= 500m(-10k/1k)
= -5v
Santosh Yadav (R) said:
1 decade ago
i=Vin-Vout/Rf+Rin
Therefore i=Vin-V2/Rin
or i=V2-Vout/Rf
The differential input voltage is zero as V1=V2=0(virtual earth)
Vin/Rin =-Vout/Rf
Vout/Vin=-Rf/Rin
Vout=Vin(-Rf/Rin)
Given value Rin or R1=10k ohm, Rf or R2=1k ohm, Vin=500mV.
We know that
Vout= Vin(-R2/Ri)
=500mV(-10k/1k)
=500mV*(-10k)
=-5000mV
Vout=-5V
Therefore i=Vin-V2/Rin
or i=V2-Vout/Rf
The differential input voltage is zero as V1=V2=0(virtual earth)
Vin/Rin =-Vout/Rf
Vout/Vin=-Rf/Rin
Vout=Vin(-Rf/Rin)
Given value Rin or R1=10k ohm, Rf or R2=1k ohm, Vin=500mV.
We know that
Vout= Vin(-R2/Ri)
=500mV(-10k/1k)
=500mV*(-10k)
=-5000mV
Vout=-5V
Shakti Dhawan said:
1 decade ago
Voltage gain=vout/vin=-(rf/rin)
vout=vin*(-rf/rin)
vout=500m(-10k/1k)
vout=-5v
vout=vin*(-rf/rin)
vout=500m(-10k/1k)
vout=-5v
Santosh N Ekbote said:
1 decade ago
Rf=10kohm; R1=1kohm; Vin=500mv;
We know that Vout= Vin(-Rf/R1);
=500m(-10k/1k)
=-5v
We know that Vout= Vin(-Rf/R1);
=500m(-10k/1k)
=-5v
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