Electronics - Operational Amplifiers - Discussion
Discussion Forum : Operational Amplifiers - General Questions (Q.No. 32)
32.
With a differential gain of 50,000 and a common-mode gain of 2, what is the common-mode rejection ratio?
Discussion:
6 comments Page 1 of 1.
Anomie said:
6 years ago
P in db =10 log Pout/pin.
db = 20 log (vout/ Vin).
db = 20 log (vout/ Vin).
Arun Kumar M said:
9 years ago
Please, can anyone explain how to calculate the value of 20log ()?
Lovish said:
1 decade ago
Cmrr = 50000/2 = 25000.
And then 20log250000 = 87.9.
And then 20log250000 = 87.9.
(2)
Suresh said:
1 decade ago
20log(Ad/Ac)
=20log(50000/2)
=87.9 dB
=20log(50000/2)
=87.9 dB
Malathy said:
1 decade ago
CMRR= differntial mode gain / common mode gain
=50000/2
=25000
To convert CMRR value to db=20log(value)=87.9db
=50000/2
=25000
To convert CMRR value to db=20log(value)=87.9db
Vishal said:
1 decade ago
Can anyone tell this ans ?
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