Electronics - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 18)
18.
What is the power in the given circuit?
Discussion:
9 comments Page 1 of 1.
Niraj kumar said:
1 decade ago
v=i*r
i=v/r
i=14/20=0.7
W=V*I
W=14*0.7=9.8
i=v/r
i=14/20=0.7
W=V*I
W=14*0.7=9.8
(1)
Dan said:
1 decade ago
Where is the .7 from?
(1)
S.sanjay said:
10 years ago
What is the formula to calculate power?
(1)
Naren said:
1 decade ago
What about this formula p=i2*r ?
Vasu said:
1 decade ago
Can use the formula like p=i^2*r or power=(V^2)/R ??
Anyways the above problem can be solved.
Anyways the above problem can be solved.
Edgar said:
1 decade ago
What about the formula of p=e2/r
Dantheman said:
1 decade ago
Lets make this easy!
P = v^2/R.
14x14 = 196.
196/20 = 9.8W.
P = v^2/R.
14x14 = 196.
196/20 = 9.8W.
Pavan said:
9 years ago
p = i^2r this is right i=v/r a/c ohm's law.
p = 7/10 * 7/10 * 20.
p = 9.8W.
p = 7/10 * 7/10 * 20.
p = 9.8W.
Omprakash said:
8 years ago
I=V/R.
I=24/20
I=0.7.
W=VI.
W=14*-0.7
W=9.
I=24/20
I=0.7.
W=VI.
W=14*-0.7
W=9.
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