Electronics - Ohm's Law - Discussion

Discussion Forum : Ohm's Law - General Questions (Q.No. 9)
9.

What is the resistor value in the given circuit?

200 omega.gif
1 komega.gif
2 komega.gif
4 komega.gif
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
10 comments Page 1 of 1.

Vinay kumar said:   8 years ago
V = 26v and I =13mA.
v = i*r .
26= 13/1000* r,
26000/13=r,
2000 = r,
2 k ohm = r,
r = 2 k Ω.

Aryan Raj SPC said:   9 years ago
Here, V = 26v and I =13mA.

R = V/I.

= 26V/13mA.
= 26V/0.013A = 2000 ohms.
= 2k 0hm.

N. VINOD KUMAR said:   1 decade ago
Given circuit in V=26 and R=13 then I=?

According to the ohm's law I = V/R.

I = 26/13.

I = 2kohms.

Lingakumar said:   1 decade ago
Ohm's law is V=IR.

So,
R = 26V/13mA

= 2K ohm.

Ram Ratan Kumar said:   1 decade ago
Ohm's law say,
V = I.R
Given that,
V = 26V,
I = 13mA,
R = V/I
= 26V/13mA
= 2 K Ohms.

KALYAN said:   1 decade ago
According to Ohm's law , V = I.R
voltage 26V
current 13ma
v=I*R
=> 26V = 13mA.R

=> R = 26V/13mA

RESISTANCE= 2 K Ohms.

Chetan said:   1 decade ago
26V, 13mA, R(resister) are connected in series,

According to Ohm's law, V = I.R

=> 26V = 13mA.R

=> R = 26V/13mA

= 2 K Ohms.

Om Shankar Pandey said:   1 decade ago
According to OHM's Law
V=I*R
and we have the value of voltage and current is 26v and 13mA respectively.
R=V/I
=26/(13*0.001)
=2k

SAKTHIVEL.S said:   1 decade ago
Given data,
voltage=26v, current=13mA,
solution:
current=13*10-3A
=13*0.001
=0.013A
ohms law,
V=IR
26V=0.013*R
R=26/0.013
=2000 ohms
=2 kilo ohms

M Abdul Hai said:   1 decade ago
26V, 13mA, R(resister) are connected in series,

According to Ohm's law, V = I.R

=> 26V = 13mA.R

=> R = 26V/13mA

= 2 K Ohms.

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