Electronics - Ohm's Law - Discussion

Discussion Forum : Ohm's Law - General Questions (Q.No. 21)

Ohm's Law

21.

If the voltage in the given circuit was cut in half, what would the current equal?

10 mA

30 mA

60 mA

90 mA

Answer: Option

Explanation:

No answer description is available. Let's discuss.

Discussion:

11 comments Page 1 of 2.

Maruthi Prapulla Kumar Yadav said: 1 decade ago

Equation is
V=IR
I=V/R
Voltage Halved so V/2
That is =18/2
V =9V
Substitute in Above Equation
I=V/R
I=9/300
I=0.03A
I=0.03*10^3 mA
I=30mA

SANTOSH said: 9 years ago

According to formula,

V = I.R
Then I = v/r.

Write value in formula.
I = 18/300 = 0.06A.
But half in circuit,
0.06/2 = 0.03A,
= 30mA.

(2)

Binktesh sharma RIET said: 1 decade ago

If the circuit cut half, so voltage is 18/2 = 9v.

So we know that v = ir.

There for i = v/r = 9/300 = 0.03 = 30mA.

(1)

Alok said: 1 decade ago

v=ir==18=i*300, now it is said in the qn that voltage is halfed.

Hence18/2=9=i*300.which come out to be 30ma

Amir shahzad.fsd. said: 9 years ago

Wo know,
V = ir.
I = v/r.

Halved voltage is cut Half. = 9.
I = 9/300 = 0.03 = 30mA.

(2)

Adearthic said: 1 decade ago

Here is the explanation : "If the voltage in the given circuit was cut in half. ".

Neeraja said: 1 decade ago

v=i*r
here the voltage is cut in half 18/2=9
i=v/r
i=9/300=0.03=30mA

Vasu said: 1 decade ago

What @samaresh said is wrong. Do check the answer out by @Neeraja.

Samarmohan mohanty said: 1 decade ago

Voltage is halved so V = 9v so,

I= V/R = 9/300 = 0.03 = 30mA.

Tanu said: 1 decade ago

Why is the voltage halved? kindly explain.

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