Electronics - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - Filling the Blanks (Q.No. 9)
9.
The power rating for the resistor in the given circuit should be at least ______.
Discussion:
2 comments Page 1 of 1.
Srujana said:
7 years ago
v=ir(750*2.5=1875) ->micros amps and mega ohms get cancelled.
Now,
P=vi(1875*750*10^-6).
= 1.40 nearly 2 watts.
Now,
P=vi(1875*750*10^-6).
= 1.40 nearly 2 watts.
Siddarth said:
9 years ago
Use ISquareR formula to solve this problem.
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