Electronics - Ohm's Law - Discussion

Discussion Forum : Ohm's Law - Filling the Blanks (Q.No. 6)
6.
The ___ rating of a resistor will increase with an increase in the surface area of the resistor.
resistance
current
power
voltage
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
9 comments Page 1 of 1.

Saumitra said:   1 decade ago
Its doubtful question, because R = Length/Conductivity*Area.

Area increases are should be decreases, (length/conductivity ratio always constant).

p =I square*R --This will tell us power decrease.

But p = v square*R---This shows power increase.

Shadan said:   7 years ago
If you have chosen which resistor has the least power then you should choose small size because power is related to size.

If the resistor has mall size then their power rating is low and vice-versa.

Philipi said:   7 years ago
R=L/A.
Increase of A, the R will be decreased.

Ohms law.
I=v/r.

Decrease in R the I and V will be increased.

Since P=IV.
the increase of both I and V it results to power increased.

Ayanangshu Banerjee said:   1 decade ago
We know that power, p=i*r*r.

So to increase the power the current will also increase then why not current.

Neelaji said:   1 decade ago
R= (pl/A) but R=V/I then current increases when only surface area increased \

Hence why not current?

POOJA MIDHA said:   8 years ago
Not related Power. Only current increase & voltage discrease according to Ohm's law.

Pradeep said:   10 years ago
R = L/A.

R = Resistance
L = Length.
A = Area.

Jagadish said:   8 years ago
A is cross sectional area not surface area.

Waseem Ahmadani said:   1 decade ago
If power changes, why not current?

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