Electronics - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - Filling the Blanks (Q.No. 3)
3.
The voltage supplying the current in the given circuit is _____.
Answer: Option
Explanation:
V = IR
= 250 x 10^-6 x 100 x 10^3
= 250 x 100 x 10^(-6+3)
= 250 x 100 x 10^-3
= 25 x 1000 x 10^-3
= 25 x 10^3 x 10^-3
= 25 x 10^0
= 25 x 1 [Anything power 0 is 1]
= 25 volts.
Discussion:
2 comments Page 1 of 1.
Chittaranjan said:
9 years ago
Simply V = IR.
= (250/1000000A) * (100*1000ohm),
= 250/1000000 * 100000,
= 25volt.
= (250/1000000A) * (100*1000ohm),
= 250/1000000 * 100000,
= 25volt.
Sundar said:
1 decade ago
V = IR
= 250 x 10^-6 x 100 x 10^3
= 250 x 100 x 10^(-6+3)
= 250 x 100 x 10^-3
= 25 x 1000 x 10^-3
= 25 x 10^3 x 10^-3
= 25 x 10^0
= 25 x 1 [Anything power 0 is 1]
= 25 volts.
= 250 x 10^-6 x 100 x 10^3
= 250 x 100 x 10^(-6+3)
= 250 x 100 x 10^-3
= 25 x 1000 x 10^-3
= 25 x 10^3 x 10^-3
= 25 x 10^0
= 25 x 1 [Anything power 0 is 1]
= 25 volts.
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