Electronics - Ohm's Law - Discussion

Discussion Forum : Ohm's Law - Filling the Blanks (Q.No. 4)
4.
The voltage across a 2.2 komega.gif resistor is ___ if 3 mA of current is flowing through it.
6.6 V
7.33 V
1.4 V
0.8 V
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
2 comments Page 1 of 1.

Lakshmi said:   9 years ago
V = IR.
V = (3 * 10^-3)(2.2 * 10^3),
V = 6.6v.

Qwerty said:   1 decade ago
V = IR.
V = (3*10^-3)(22*10^2).
V = 66*10^-1.
V = 6.6V.

Post your comments here:

Your comments will be displayed after verification.